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What will be the output of the following code?
public class MyClass {
public static void main(String[] args) {
int x = 10;
changeValue(x);
System.out.println(x);
}
public class MyClass {
public static void main(String[] args) {
int x = 10;
changeValue(x);
System.out.println(x);
}
public static void changeValue(int value) {
value = 20;
}
}
value = 20;
}
}
- a)10
- b)20
- c)Compilation Error
- d)Runtime Error
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
What will be the output of the following code?public class MyClass { p...
In Java, method parameters are passed by value. When 'changeValue' method is called, a copy of the value of 'x' is passed. The method modifies the copy, but it does not affect the original variable 'x'.
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Community Answer
What will be the output of the following code?public class MyClass { p...
Answer:
The output of the code will be 10.
Explanation:
When the code is executed, the following steps occur:
1. The variable x is declared and initialized with the value 10.
2. The method changeValue() is invoked and the value of x is passed as an argument.
3. In the changeValue() method, a new variable value is declared and initialized with the value of x, which is 10.
4. The value of value is then changed to 20.
5. However, this change does not affect the original value of x because Java passes arguments by value, which means that a copy of the variable's value is passed to the method. Therefore, changing the value of the parameter value does not modify the original variable x.
6. The method changeValue() completes execution and the control returns to the main() method.
7. The value of x is printed using the System.out.println() statement, which still retains its original value of 10.
Therefore, the output of the code is 10.
The output of the code will be 10.
Explanation:
When the code is executed, the following steps occur:
1. The variable x is declared and initialized with the value 10.
2. The method changeValue() is invoked and the value of x is passed as an argument.
3. In the changeValue() method, a new variable value is declared and initialized with the value of x, which is 10.
4. The value of value is then changed to 20.
5. However, this change does not affect the original value of x because Java passes arguments by value, which means that a copy of the variable's value is passed to the method. Therefore, changing the value of the parameter value does not modify the original variable x.
6. The method changeValue() completes execution and the control returns to the main() method.
7. The value of x is printed using the System.out.println() statement, which still retains its original value of 10.
Therefore, the output of the code is 10.
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